A laboratory manual gave precise instructions for carrying out the reaction described by the chemical equation, C2H6O + O2 C2H4O2 + H2O. It stated that if you bubble oxygen gas through a solution containing the reactant for 24 hours then the yield of C2H4O2 would be 7.50% of the theoretical amount. If you desire to produce 700. grams of the C2H4O2 in a single batch, how many kg of C2H6O should you begin with?

Question

Larissa Hansen

Chemistry

10 July, 08:25

A laboratory manual gave precise instructions for carrying out the reaction described by the chemical equation, C2H6O + O2 C2H4O2 + H2O. It stated that if you bubble oxygen gas through a solution containing the reactant for 24 hours then the yield of C2H4O2 would be 7.50% of the theoretical amount. If you desire to produce 700. grams of the C2H4O2 in a single batch, how many kg of C2H6O should you begin with?

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Answers (1)

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Lee Berger · Answer 1

C2H6O + O2 - - - > C2H4O2 + H2O

using the molar masses:-

24 + 6 + 16 g of C2H6O produces 24 + 4 + 32 g C2H4O2 (theoretical)

46 g produces 60g

60 g C2H4O2 is produced from 46g C2H6O

1g ... 46/60 g

700g ... (46/60) * 700 Theoretically

But as the yield is only 7.5%

the required amount is ((46/60) * 700) / 0.075 = 7155.56 g

= 7.156 kg to nearest gram. Answer