If you wanted to neutralize 4.00g NaOH, what volume of 1.0 M HCl would you need?

This is a simple acid base reaction.

To neutralize all NaOH, the moles in 4.00g of NaOH should be equal to the moles of HCl since the stoichiometric ratio between NaOH and HCl is 1 : 1.

NaOH + HCl → NaCl + H₂O

Molar mass of NaOH = (23 + 16 + 1) g mol⁻¹

Moles in NaOH = mass / molar mass = 4.00 g / 40 g mol⁻¹ = 0.1 mol

HCl moles = 0.1 mol

concentration = number of moles (mol) / volume (L)

Hence HCl volume = 1.0 mol/L x 0.1 mol = 0.1 L = 100.0 mL

To neutralize 4.00 g of NaOH, 100.0 mL of 1.0 M HCl is needed.