You carefully weigh out 11.00 g of caco3 powder and add it to 44.55 g of hcl solution. you notice bubbles as a reaction takes place. you then weigh the resulting solution and find that it has a mass of 51.04 g. the relevant equation is caco3 (s) + 2hcl (aq) âh2o (l) + co2 (g) + cacl2 (aq) assuming no other reactions take place, what mass of co2 was produced in this reaction?

Question

Reilly Mooney

Chemistry

24 March, 08:49

You carefully weigh out 11.00 g of caco3 powder and add it to 44.55 g of hcl solution. you notice bubbles as a reaction takes place. you then weigh the resulting solution and find that it has a mass of 51.04 g. the relevant equation is caco3 (s) + 2hcl (aq) âh2o (l) + co2 (g) + cacl2 (aq) assuming no other reactions take place, what mass of co2 was produced in this reaction?

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Devyn Hernandez · Answer 1

The bubbles that were observed after the mixing of the two substances is one of the products of the reaction. It is the carbon dioxide that is produced. To determine the mass of this gas produced, we need to remember the Law of conservation of mass where mass cannot be created or destroyed. With this, we can say that the total mass that goes in a process should be equal to the mass that is goes out of the process no matter what the reaction is. We do as follows:

Mass of reactants = mass of products

11.00 + 44.55 = 51.04 + mass of carbon dioxide

mass of carbon dioxide = 4.51 g