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30 August, 02:44

What quantity of gas, in moles, is contained in 26.97L at STP?

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  1. 30 August, 02:52
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    The answer to your question is 1.09 moles

    Explanation:

    Data

    Volume = 26.97 l

    Temperature = 20°C

    Pressure = 1 atm

    Gas constant = 0.082 atm l / mol°K

    Process

    1. - Convert temperature to °K

    Temperature = 26.97 + 273

    = 299.97°K

    2. - Write the formula

    PV = nRT

    -solve for moles

    n = PV / RT

    -substitution

    n = (1 x 26.97) / (0.082 x 299.97)

    -Simplification

    n = 26.97 / 24.6

    -Result

    n = 1.09
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