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3 August, 15:13

Industrially, vanadium metal, which is used in steel alloys, can be obtained by reacting vanadium (V) oxide with calcium at high temperatures: 5Ca + V2O5 longrightarrow 5CaO + 2V In one process, 1.540 * 103 g of V2O5 react with 1.960 * 103 g Ca. Calculate the theoretical yield of V. Calculate the percent yield if 825.0 g of V are obtained.

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  1. 3 August, 15:21
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    The percent yield is 95.64 %

    Explanation:

    Step 1: Data given

    Mass of V2O5 = 1540 grams

    Mass of Ca = 1960 grams

    actual yield of V = 825 grams

    Molar mass V2O5 = 181.88 g/mol

    Molar mass of Ca = 40.08 g/mol

    Step 2: The balanced equation

    5Ca + V2O5 → 5CaO + 2V

    Step 3: Calculate moles

    Moles = mass / molar mass

    Moles V2O5 = 1540 grams / 181.88 g/mol

    Moles V2O5 = 8.467 moles

    Moles Ca = 1960 grams / 40.08 g/mol

    Moles Ca = 48.90 moles

    Step 4: Calculate limiting reactant

    For 5 moles Ca we need 1 mol V2O5 to produce 2 moles V and 5moles CaO

    V2O5 is the limiting reactant. It will completely be consumed (8.467 moles).

    Ca is in excess. There will react 5*8.467 = 42.335 moles

    There will remain 48.90 * 42.335 = 6.565 moles

    Step 5: Calculate moles V

    For 5 moles Ca we need 1 mol V2O5 to produce 2 moles V and 5moles CaO

    For 8.467 moles V2O5 we'll have 2*8.467 = 16.934 moles

    Step 6: Calculate mass V

    Mass V = moles V * molar mass V

    Mass V = 16.934 moles * 50.94 g/mol

    Mass V = 862.6 grams = theoretical yield

    Step 7: Calculate % yield

    % yield = (actual yield / theoretical yield) * 100%

    % yield = (825.0 grams / 862.6 grams) * 100%

    % yield = 95.64 %

    The percent yield is 95.64 %
  2. 3 August, 15:33
    0
    95.59%

    Explanation:

    Calculate the theoretical yield when 1.54 * 103 g of V2O5 react with 1.96 * 103 g of Ca.

    First, we find the limiting reactant:

    1.54 * 103 g · 1 mol/181.881 g = 8.47 mol V2O5

    1.96 * 103 g · 1 mol/40.078 g = 48.9 mol

    The number of moles of Ca to react completely with 8.47 mol V2O5 is 8.47 mol V2O5 · 5 mol Ca/1 mol V2O5 = 42.4 mol

    So Ca is in excess and we should use the molar amount of V2O5 to determine the theoretical yield of V.

    8.47 mol V2O5 · 2 mol V/1 mol V2O5 = 16.9 mol V

    Percent Yield What is the percent yield if 825 g of V are obtained?

    First, find out how many grams the theoretical yield of V represents: 16.9 mol · 50.941 g/mol = 863 g

    Then just divide the actual yield (given) by the theoretical yield: 825g/863g = 0.9559 * 100% = 95.59%
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