Ask Question
21 October, 10:06

What pressure is required to compress 189.0 liters of air at 1.00 atm into a cylinder whose volume is 28.0 liters

+2
Answers (1)
  1. 21 October, 10:17
    0
    6.75atm

    Explanation:

    The following data were obtained from the question:

    V1 = 189L

    P1 = 1atm

    V2 = 28L

    P2 = ?

    Using Boyle's law equation P1V1 = P2V2 the pressure required to compress the gas can be obtained as follows:

    P1V1 = P2V2

    1 x 189 = P2 x 28

    Divide both side by 28

    P2 = 189/28

    P2 = 6.75atm

    Therefore, the pressure require to compress the gas is 6.75atm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What pressure is required to compress 189.0 liters of air at 1.00 atm into a cylinder whose volume is 28.0 liters ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers