Ask Question
24 August, 12:38

How many moles of NF3 contain 2.55 x 10^24 Fluorine atoms

+1
Answers (1)
  1. 24 August, 12:58
    0
    moles of O = atom / avogadro's number = 2.55*10^24 / 6.022*10^23 = 4.23 mol

    since each N2O3 contains 3 O atoms:

    moles of N2O3 = moles of O / 3 = 1.41 mol
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many moles of NF3 contain 2.55 x 10^24 Fluorine atoms ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers