Suppose we have a solution of lead nitrate, pb (no3) 2 (aq). a solution of nacl (aq) is added slowly until no further precipitation occurs. the precipitate is collected by filtration, dried, and weighed. a total of 17.19 g of pbcl2 (s) is obtained from 200.0 ml of the original solution. calculate the molarity of the pb (no3) 2 (aq) solution.

The solution to calculate the molarity of the Pb (NO3) 2 (aq) is below;

(17.19 g PbCl2) / (278.1164 g PbCl2/mol) x (1 mol Pb (NO3) 2 / 1 mol PbCl2) / (0.2000 L)

Be careful on inserting the data on the calculator when you are solving it may give you an inaccurate answer.

= 0.3090 mol Pb (NO3) 2/L

The molarity of the pb (no3) 2 (aq is 0.3090 mol Pb (NO3) 2/L