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11 March, 21:09

A volume of 5.0 L of gas at a temperature of 25°C is cooled to a temperature of - 120°C at constant pressure. What is the new volume of the gas?

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  1. 11 March, 21:33
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    V1 = 5L = 5000ml V2 = ?

    T1 = 25°C = 25+273 T2 = - 120°C

    = 297K = - 120+273

    = 153K

    By Charles Law,

    V1/T1 = V2/T2

    5000/297 = V2/153

    By solving,

    V2 = 2.576L
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