What molality of pentane is obtained by dissolving 15 g pentane, c5h12, in 245.0 g hexane, c6h14?

Answer

The molality of pentane will be be 0.84 Molality

Data given

mass of pentane = 15g molar mass of pentane = 72.15 mass of solvent (hexane) = 245.0 g = 0.245 Kg

Solution

Molality = (given mass : molar mass) : 1 Kg of solvent Molality = (15 : 72.15) : 0.245 Kg Molality = 0.84