You breathe in 3.0 L of pure oxygen at 298 K and 1,000 kPa to fill your lungs. How many moles of oxygen did you take in? Use the ideal gas law: PV = nRT where R=8.31 L-kPa/mol-K

A. 0.05 MOLE

B. 1.21 MOLES

C. 2.42 MOLES

D. 20.0 MOLES

Question

Gianni Griffin

Chemistry

9 February, 00:48

You breathe in 3.0 L of pure oxygen at 298 K and 1,000 kPa to fill your lungs. How many moles of oxygen did you take in? Use the ideal gas law: PV = nRT where R=8.31 L-kPa/mol-K

A. 0.05 MOLE

B. 1.21 MOLES

C. 2.42 MOLES

D. 20.0 MOLES

+5

Answers (1)

Know the Answer?

Boston Miranda · Answer 1

Option B.

Explanation:

Let's replace the data given in the formula of Ideal Gases Law.

P. V = n. R. T

3L. 1000kPa = n. 8.31 L. kPa/mol. K. 298K

(3L. 1000 kPa) / (8.31 L. kPa/mol. K. 298K) = n

1.21 moles

You breathe in 3.0 L of pure oxygen at 298 K and 1,000 kPa to fill your lungs. How many moles of oxygen did you take in? Use the ideal gas law: PV = nRT where R=8.31 L-kPa/mol-KA. 0.05 MOLEB. 1.21 MOLESC. 2.42 MOLESD. 20.0 MOLES

You breathe in 3.0 L of pure oxygen at 298 K and 1,000 kPa to fill your lungs. How many moles of oxygen did you take in? Use the ideal gas law: PV = nRT where R=8.31 L-kPa/mol-K

A. 0.05 MOLE

B. 1.21 MOLES

C. 2.42 MOLES

D. 20.0 MOLES