Ask Question
3 May, 06:51

A solution of koh required 31.3 ml of 0.118 m hcl to reach neutralization. what mass of koh was in the titrated sample?

+2
Answers (1)
  1. 3 May, 07:09
    0
    Neutralization reaction is a reaction that involves reaction of a base/alkali and an acid forming salts and water as the only products. In this case;

    KOH (aq) + 2HCl (aq) = H2O (l) + 2KCl (aq)

    Moles of HCl used = (31.3/1000) * 0.118 = 0.00369 moles

    Using mole ratio of KOH : HCl = 1:2, the mole of KOH will be;

    0.00369 : 2 = 0.001845 Moles

    But, 1 mole of KOH = 56 g

    Therefore; 0.001845 moles will have; 0.001845 * 56 = 0.10332g

    Hence the mass of KOH titrated was 0.10332g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A solution of koh required 31.3 ml of 0.118 m hcl to reach neutralization. what mass of koh was in the titrated sample? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers