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28 July, 20:00

In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 2.00mm away. What is the initial acceleration of the proton after it is released?

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  1. 28 July, 20:11
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    F = m. a

    = mass x acceleration

    So,

    a = F / m

    Where,

    F is coulomb repulsion.

    k q q / r^2

    with,

    k = 9 x 10^9 in SI units (q in C and r in m)

    Hence,

    a = 2.40 * 10^11 m/s^2
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