In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 2.00mm away. What is the initial acceleration of the proton after it is released?

Question

Doobie

Chemistry

28 July, 20:00

In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 2.00mm away. What is the initial acceleration of the proton after it is released?

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Jarrett Carrillo · Answer 1

F = m. a

= mass x acceleration

So,

a = F / m

Where,

F is coulomb repulsion.

k q q / r^2

with,

k = 9 x 10^9 in SI units (q in C and r in m)

Hence,

a = 2.40 * 10^11 m/s^2