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18 October, 13:34

How many mL of a 4.50M NaBr solution are needed to make 250 mL of a 0.75M solution of NaBr?

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  1. 18 October, 13:40
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    M1V1=M2V2

    (4.50) (x) = (0.75) (250)

    (4.50) (x) = 187.5

    x=41.67 mL

    You might want to double check the formula used, but as a chem student I’m confident this is right
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