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11 June, 13:37

What is the ph of a buffer prepared by adding 0.607 mol of the weak acid ha to 0.609 mol of naa in 2.00 l of solution? the dissociation constant ka of ha is 5.66*10-7?

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  1. 11 June, 13:45
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    Given:

    0.607 mol of the weak acid

    0.609 naa

    2.00 liters of solution

    The solution for finding the ph of a buffer:

    [HA] = 0.607 / 2.00 = 0.3035 M

    [A-] = 0.609 / 2.00 = 0.3045 M

    pKa = 6.25

    pH = 6.25 + log 0.3045 / 0.3035 = 6.25 is the ph buffer prepared.
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