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10 February, 06:29

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 400. mL of a solution that has a concentration of Na + ions of 1.00 M?

Express your answer to three significant figures and include the appropriate units.

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  1. 10 February, 06:53
    0
    137g of Na3PO4

    Explanation:

    We sort of need to work backwards in this case. First figure out how many total Na + ions there will be:

    C = n/V

    1 = n/0.4

    n=2.5

    The solution will contain 2.5 moles of Na + ions. Now, notice that in Na3PO4 there are 3 Na atoms per molecule. That means if there are 2.5 moles of Na, there are 3 times LESS moles of Na3PO4.

    2.5/3 = 0.833

    Therefore 0.833 moles of Na3PO4 will be required. Now it's just a simple matter of converting to grams (using molar mass of Na3PO4):

    n = m/MM

    0.833 = m/164

    m = 137

    A total of 137g of Na3PO4 will be required.
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