In the reaction K2CrO4 (aq) + PbCl2 (aq) → 2KCl (aq) + PbCrO4 (s), how many grams of PbCrO4 will precipitate out from the reaction between 500.0 milliliters of 3.0 M K2CrO4 in an excess of PbCl2?

A. 1.5 grams

B. 3.0 grams

C. 480 grams

D, 150 grams

I don't understand how i would find the answer.

Question

Trystan Morrow

Chemistry

10 June, 15:20

In the reaction K2CrO4 (aq) + PbCl2 (aq) → 2KCl (aq) + PbCrO4 (s), how many grams of PbCrO4 will precipitate out from the reaction between 500.0 milliliters of 3.0 M K2CrO4 in an excess of PbCl2?

A. 1.5 grams

B. 3.0 grams

C. 480 grams

D, 150 grams

I don't understand how i would find the answer.

+4

Answers (1)

Know the Answer?

Giovani Ware · Answer 1

This is a stoichiometry question. but the answer is not listed.

500.0 ml (1 Liter / 1000 mL) (3.0 moles / 1 L) (1 mole PbCrO4 / 1 mole K2CrO40) (194 grams / 1 mole K2CrO4) = 291 grams of K2CrO4 produced.

In the reaction K2CrO4 (aq) + PbCl2 (aq) → 2KCl (aq) + PbCrO4 (s), how many grams of PbCrO4 will precipitate out from the reaction between 500.0 milliliters of 3.0 M K2CrO4 in an excess of PbCl2?A. 1.5 gramsB. 3.0 gramsC. 480 gramsD, 150 gramsI don't understand how i would find the answer.