Ask Question
8 July, 08:25

49.7 mL of a solution of NaOH is needed to neutralize a solution that contains 1.86 g of H2504 in 20.00 mL of water. What is the molarity of the NaOH solution?

H2SO4 + 2 NaOH - -> 2H2O + Na2SO4

1) 0.763 M

2) 0.0404 M

3) 1.13 M

4) 0.481 M

5) 0.602 M

6) 2.23 M

7) 1.81 M

8) 2.94 M

+1
Answers (1)
  1. 8 July, 08:30
    0
    1) C NaOH = 0.763 M

    Explanation:

    H2SO4 + 2 NaOH → 2 H2O + Na2SO4

    ∴ V NaOH = 49.7 mL = 0.0497 L

    ∴ m H2SO4 = 1.86 g

    ∴ V sln = 20.00 ml = 0.020 L

    ∴ Mw H2SO4 = 98.079 g/mol

    ⇒ n H2SO4 = (1.86 g) (mol / 98.079 g) = 0.019 mol H2SO4

    ⇒ n NaOH = (0.019 mol H2SO4) (2 mol NaOH / mol H2SO4) = 0.038 mol NaOH

    ⇒ C NaOH = 0.038 mol / 0.0497 L = 0.763 M
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “49.7 mL of a solution of NaOH is needed to neutralize a solution that contains 1.86 g of H2504 in 20.00 mL of water. What is the molarity ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers