Ask Question
11 September, 05:10

What is the limiting reactant in

2K + F2 = 2KF

If you have 10 molecules of K and 10 molecules of F2?

+1
Answers (1)
  1. 11 September, 05:39
    0
    The limiting reactant is the K

    Explanation:

    This is the reaction:

    2 K + F₂ → 2KF

    2 moles of potassium react with 1 mol of fluorine

    Let's determine the moles:

    6.02x10²³ molecules are contained in 1 mol

    10 molecules are contained in (10. 1) / NA = 1.66x10⁻²³ moles

    For 1 mol of flourine, we need 2 moles of K

    If we have 1.66x10⁻²³ moles of Fl₂, we will need the double of K

    For 2 moles of K, we need 1 mol of Fl₂

    If we have 1.66x10⁻²³ moles of K, we will need the half of Fl₂

    Then, the limiting reactant is the K
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the limiting reactant in 2K + F2 = 2KF If you have 10 molecules of K and 10 molecules of F2? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers