Calculate the molality of a solution containing 257 g glucose (c6h12o6) dissolved in 1.62 l of water. assume a density of 1.00 g/ml for water.

Molality is defined as the number of moles of solute in 1 kg of solvent.

since density and volume has been given we can calculate the mass of water

mass = density x volume

mass = 1.00 g/mL x 1620 mL = 1620 g

number of moles of glucose - 257 g / 180 g/mol = 1.43 mol

number of moles of glucose in 1620 g - 1.43 mol

therefore number of moles in 1000 g - 1.43 mol / 1.620 kg = 0.883 mol/kg

therefore molality is 0.883 mol/kg