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17 October, 19:20

Ethane, C2H6, burns in oxygen. First write a balanced equation for this combustion reaction. What mass of oxygen, in grams, is required for complete combustion of 13.6 g of ethane

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  1. 17 October, 19:39
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    We need 50.6 grams of oxygen

    Explanation:

    Step 1: Data given

    Mass of ethane = 13.6 grams

    Molar mass of ethane = 30.07 g/mol

    Step 2: The balanced equation

    2C2H6 + 7O2 → 4CO2 + 6H2O

    Step 3: Calculate moles ethane

    Moles ethane = mass ethane / molar mass ethane

    Moles ethane = 13.6 grams / 30.07 g/mol

    Moles ethane = 0.452 moles

    Step 4: Calculate moles oxygen

    For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

    For 0.452 moles ethane we need 3.5*0.452 = 1.582 moles O2

    Step 5: Calculate mass O2

    Mass O2 = moles O2 * molar mass O2

    Mass O2 = 1.582 moles * 32.0 g/mol

    Mass O2 = 50.6 grams

    We need 50.6 grams of oxygen
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