Answer how many moles of sodium will react with 2.6l of cl2 gas at 1.15 atm

The chemical equation for the reaction is,

2 Na + Cl₂ → 2 NaCl

Before applying stoichiometry, first you will have to find the moles of Cl₂ at given conditions using Ideal gas equation.

n = P V / R T

As, temperature is not given, so put standard Temperature i. e. 273 K, or if you are provided with it simply put its value So,

n = (1.15 atm * 2.6 L) : (0.0821 atm. L. mol⁻¹. K⁻¹ * 273 K)

n = 0.133 mol of Cl₂

Now,

According to Balance equation,

1 mole Cl₂ required = 2 moles of Na

So,

0.133 mol Cl₂ will require = X moles of Na

Solving for X,

X = (0.133 mol * 2 mol) : 1 mol

X = 0.266 moles of Na