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13 May, 15:49

How many molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium? 4Na + O2 - > 2Na2O A. 11.69 x 1023 molecules of Na2O

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  1. 13 May, 16:19
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    7.04 * 10²⁴ molecules of Na₂O

    Explanation:

    1) Balanced chemical equation (given):

    4 Na (s) + O₂ (g) → 2Na₂O (s)

    2) Mole ratio:

    1 mol O₂ : 2 mol Na₂O

    3) Number of moles of O₂ in 187 grams of oxygen:

    Molar mass O₂ = 32.00 g/mol

    Number of moles = mass in grams / molar mass = 187 g / 32.00 g/mol = 5.844 mol

    4) Number of moles of Na₂O:

    Proportion: 1 mol O₂ / 2 mol Na₂O = 5.844 mol O₂ / x

    x = 5.844 mol O₂ (2 mol Na₂O / 1 mol O₂) = 11.688 mol Na₂O

    5) Number of molecules

    Number of molecules = number of moles * Avogadro's number

    Number of molecules = 11.688 mol * 6.022 * 10²³ molecules/mol =

    = 7.04 * 10 ²⁴ molecules ← answer

    The answer is rounded to three significant figures.
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