Ask Question
19 April, 21:12

Choose the statements about benzene that are correct.

all benzene hydrocarbons are ChHp-2

All C-C bonds share 2 pairs of electrons,

Three C-C bonds share 2 pairs of electrons,

All of the C-C bonds are actually identical,

The structure of the molecule is closed like a ring structure,

+5
Answers (1)
  1. 19 April, 21:34
    0
    All of the C-C bonds are actually identical,

    The structure of the molecule is closed like a ring structure,

    Explanation:

    1) all benzene hydrocarbons are ChHp-2 ⇔ this is false the formula for benzene is C6H6 (CnHn).

    2) All C-C bonds share 2 pairs of electrons ⇔ False

    There are not enough electrons to form double bonds on all the carbon atoms

    3) Three C-C bonds share 2 pairs of electrons ⇔ False

    Since there are not enough electrons to form double bonds on all the carbon atoms, although the electrons do strengthen all of the bonds on the ring equally.

    4) All of the C-C bonds are actually identical ⇔ correct

    ⇒The actual structure of benzene is a resonance hybrid, with six delocalised π-electrons. (4n + 2 = π)

    ⇒Due to this structure with delocalised π-electrons, the structure of benzene is very stable and it's reactivity quite low.

    ⇒ All the C-C bonds of bezene have sp2-sp2 overlap on both sides, what makes them to form 3 π-bonds

    5) The structure of the molecule is closed like a ring structure ⇔ correct

    Since there are not enough electrons to form double bonds on all the carbon atoms, although the electrons do strengthen all of the bonds on the ring equally. This results in symmetric molecular orbital. The delocalisation of the electrons is also known as aromaticity or ring structure, what gives benzene a great stability.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Choose the statements about benzene that are correct. all benzene hydrocarbons are ChHp-2 All C-C bonds share 2 pairs of electrons, Three ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers