Calculate the molality of a solution containing 17.85 g of glycerol (C3H8O3) in 87.4 g of ethanol (C2H5OH).

Molality for the solution is 2.22 m

Explanation:

Molality is a sort of concentration. Indicated the moles of solute in 1kg of solvent. → mol/kg

Let's determine the moles of solute (mass / molar mass)

17.85 g / 92 g/mol = 0.194 moles

Let's convert the mass of solvent (g) to kg

87.4 g. 1kg / 1000 g = 0.0874 kg

Mol/kg → Molality

0.194 mol / 0.0874 kg = 2.22 m