The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT.

a.) 0.13 J/g-°C

b.) 0.20 J/g-°C

c.) 0.78 J/g-°C

d.) 0.46 J/g-°C

Question

Daniel Liu

Chemistry

26 April, 06:48

The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT.

a.) 0.13 J/g-°C

b.) 0.20 J/g-°C

c.) 0.78 J/g-°C

d.) 0.46 J/g-°C

+4

Answers (1)

Know the Answer?

Tabitha Briggs · Answer 1

It is so simple and direct substitution in the formula of:

C = Q / m ΔT

when C is specific heat constant

and Q is heat energy of joul

and m is the mass

and ΔT is the change in temperature

and when we have Q = 293 J & m = 25 g & ΔT = 15 °C so by substitution:

∴C = 293 / (25*15)

= 0.78 J/g-°C

∴ 0.78 J/g-°C is the correct answer

The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT.a.) 0.13 J/g-°Cb.) 0.20 J/g-°Cc.) 0.78 J/g-°Cd.) 0.46 J/g-°C

The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT.

a.) 0.13 J/g-°C

b.) 0.20 J/g-°C

c.) 0.78 J/g-°C

d.) 0.46 J/g-°C