A chemist prepares a solution of copper (l) sulfate (CuSo4) by measuring out 11.7 g of copper (II) sulfate into a 350. mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper (II) sulfate solution. Be sure your answer has the correct number of significant digits molL x 1

0.209 mol/L

Explanation:

Given data

Mass of copper (lI) sulfate (solute) : 11.7 g Volume of solution: 350 mL = 0.350 L

The molar mass of copper (Il) sulfate is 159.61 g/mol. The moles corresponding to 11.7 grams are:

11.7 g * (1 mol/159.61 g) = 0.0733 mol

The molarity of copper (Il) sulfate is:

M = moles of solute / liters of solution

M = 0.0733 mol / 0.350 L

M = 0.209 mol/L