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28 March, 02:56

A 55-mL solution of H2SO4 is completely neutralized by 46 mL of 1.0M NaOH. What is the concentration of the H2SO4∆H2SO4 (aq) + 2NaOH (aq) → Na2SO4 (aq) + 2H2O (l)

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  1. 28 March, 03:11
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    H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O

    v (NaOH) = 46 ml=0.046 l

    c (NaOH) = 1.0 mol/l

    v (H₂SO₄) = 55 ml=0.055 l

    n (NaOH) = v (NaOH) * c (NaOH)

    n (H₂SO₄) = 0.5n (NaOH)

    c (H₂SO₄) = n (H₂SO₄) / v (H₂SO₄) = 0.5*v (NaOH) * c (NaOH) / v (H₂SO₄)

    c (H₂SO₄) = 0.5*0.046*1.0/0.055=0.418 mol/l

    The concentration of the H₂SO₄ is 0.418M.
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