Ammonia reacts with oxygen according to the equation 4NH3 (g) + 5O2 (g) →4NO (g) + 6H2O (g),ΔHrxn=-906 kJ Calculate the heat (in kJ) associated with the complete reaction of 155 g of NH3.

Question

Cameron Cochran

Chemistry

16 October, 02:03

Ammonia reacts with oxygen according to the equation 4NH3 (g) + 5O2 (g) →4NO (g) + 6H2O (g),ΔHrxn=-906 kJ Calculate the heat (in kJ) associated with the complete reaction of 155 g of NH3.

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Cierra Rogers · Answer 1

Answer is: 2065.15 kJ.

Balanced chemical reaction: 4NH₃ + 5O₂ → 4NO + 6H₂O, ΔHrxn=-906 kJ.

m (NH₃) = 155 g.

n (NH₃) = m (NH₃) : M (NH₃).

n (NH₃) = 155 g : 17 g/mol.

n (NH₃) = 9.118 mol.

Make proportion: 4 mol (NH₃) : 906 kJ = 9.118 mol : Q.

Q = 906 kJ · 9.118 mol / 4 mol.

Q = 2065.15 kJ.