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Joey
Chemistry
14 November, 13:44
How is C10 H16 + 8 Cl2 + 10C + 16 HCL written
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Micheal Bridges
14 November, 14:14
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10 C-8/5 - 16 e - → 10 C0 (oxidation)
16 Cl0 + 16 e - → 16 Cl-I (reduction)
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