What volume of oxygen gas, in milliliters, is required to react with 0.640 g of SO2 gas at STP?

11.2 mL

22.4 mL

112 mL

224 m

SO2 + O2 - - - > SO3. Moles of SO2 = 0.64/32+16X2 = 0.01mole. According to stoichiometry, moles of SO2 = moles of O2 = 0.01mol. Therefore volume of oxygen gas at STP = 22.4 x moles of O2 = 22.4 x 0.01 = 0.224 = 224mL.