Marc was told his dinner would be ready at 18:00. He left his house at 12:00 and traveled in his car at an average speed of 45 mph to his moms house 300 miles away. Did Marc make it in time for dinner

The answer to your question is: Marc won't be on time for dinner.

Explanation:

Data

dinner = 18:00

left = 12:00

speed = 45 mph

distance = 300 miles

time = ?

Formula

speed = distance / time

time = distance / speed

time = 300 / 45

time = 6.7 hours

Then

from 12:00 to 18:00 there are 6 hours

Marc won't be on time.

Marc didn't make it in time for dinner

Explanation:

Marc left home 12:00 p. m, and his dinner was ready 6:00 p. m (18:00), he needed;

18:00 - 12:00 = 6 hrs

Marc needed to spend at most 6 hours on the road in order to get to his mom's house early.

The unit mph means "miles per hour"

The formula to be used here is

speed (in mph) = distance (in miles) : time (in hours)

The speed and distance are 45 mph and 300 miles respectively (as provided in the question). The time spent on the road is unknown.

Hence,

45 mph = 300 miles : time

time = 300 : 45

time = 6.67 hours

In order to get the actual time (in hours and minutes) spent on the road, the ".67" in the answer above will have to be converted to minutes because the clock is not represented in decimal places.

After the decimal, 100 will represent 60 minutes hence,

100 ⇒ 60 mins

67 ⇒ x mins

x = (60 * 67) : 100

x = 40.2 mins

Hence, it must have taken Marc 6 hours and 40 minutes to get to his mom's house, meaning he arrived his mom's house at 18:40 (6:40 p. m). This means Marc arrived late for his dinner.