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4 January, 21:14

If a solution had an [OH-] = 3.00 x 10-10 moles/liter, what would be the pH value of this solution? 3.53 4.48

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  1. 4 January, 21:39
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    4.48

    Explanation:

    p[OH-] = - log (3.00 * 10^-10) = 9.52

    pH + pOH = 14

    pH = 14 - 9.52 = 4.48
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