What is the volume of 2.10 moles of chlorine gas (Cl2) at 273 K and 1.00 atm?

10.7 L

22.4 L

47.1 L

82.0 L

Ideal gas law:

PV=nRT ⇒ V=nRT / P

P=pressure=1 atm

V=volume

n=number moles=2.10 moles

R=0,082 Atm l/ºK mol

T=temperature=273 K

V = (2.10 moles*0.082 (atm l) / º (K mol) * 237ºK) / 1 atm=47.01 litres

47.1 L