Which substance gives up electrons in this in this reaction? 4Al (s) + 3O2 (g) → 2Al2O3 (s) O2 Al2 O3 Al

Question

Zion Downs

Chemistry

10 February, 01:34

Which substance gives up electrons in this in this reaction? 4Al (s) + 3O2 (g) → 2Al2O3 (s) O2 Al2 O3 Al

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Vaughn Cunningham · Answer 1

Al

Step-by-step explanation:

The overall reaction is

4Al + 3O₂ ⟶ 2Al₂O₃

The Al atoms lose three electrons each to form Al³⁺ ions:

4Al ⟶ 4Al³⁺ + 12e⁻

The O₂ molecules gain those 12 electrons each to form O²⁻ ions.

3O₂ + 12e⁻ ⟶ 6O²⁻

The Al³⁺ and O²⁻ ions combine to form Al₂O₃.

4Al³⁺ + 6O²⁻ ⟶ 2Al₂O₃.