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24 January, 18:11

Hydrazine is a weak base, kb=3.0x10^-6. find the ph of an aqueous 2.0 m solution of its conjugate acid

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  1. 24 January, 18:17
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    Answer is: pH of hydrazine conjugate acid is 4.088.

    Chemical reaction: N₂H₅⁺ + H₂O ⇄ N₂H₄ + H₃O⁺.

    [N₂H₅⁺] = 2.0 M.

    [N₂H₄] = [H₃O⁺] = x.

    Kb (N₂H₄) = 3.0·10⁻⁶.

    Kb·Ka = 1.00·10⁻¹⁴.

    Ka (N₂H₅⁺) = 1.00·10⁻¹⁴ : 3.0·10⁻⁶.

    Ka = 3.33·10⁻⁹.

    Ka = [N₂H₄]·[H₃O⁺] / [N₂H₅⁺].

    3.33·10⁻⁹ = x² / 2.0 M.

    x = [H₃O⁺] = √3.33·10⁻⁹ · 2.0 M.

    [H₃O⁺] = 8.1·10⁻⁵ M.

    pH = - log[H₃O⁺].

    pH = - log (8.1·10⁻⁵ M).

    pH = 4.088.
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