He standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li + (aq) + e-→li (s) - 3.04 cl2 (g) + 2e-→2cl - (aq) + 1.36 in a galvanic cell, the two half-reactions combine to 2li (s) + cl2 (g) →2li + (aq) + 2cl - (aq) calculate the cell potential of this reaction under standard reaction conditions. express your answer with the appropriate units.

Question

Landen Moon

Chemistry

19 June, 15:54

He standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li + (aq) + e-→li (s) - 3.04 cl2 (g) + 2e-→2cl - (aq) + 1.36 in a galvanic cell, the two half-reactions combine to 2li (s) + cl2 (g) →2li + (aq) + 2cl - (aq) calculate the cell potential of this reaction under standard reaction conditions. express your answer with the appropriate units.

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Lila Dudley · Answer 1

2 Li (s) + Cl₂→ 2 Li⁺ (aq) + 2Cl⁻ (aq)

The cell potential of the reaction above is + 4.40V

calculation

Cell potential = ∈° red - ∈° oxidation

in reaction above Li is oxidized from oxidation state 0 to + 1 therefore the∈° oxid = - 3.04

Cl is reduce from oxidation state 0 to - 1 therefore the ∈°red = + 1.36 V

cell potential is therefore = + 1.36 v - - 3.04 = + 4.40 V