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15 November, 22:48

How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?

a

0.001 mL

b

none of the above

c

10 mL

d

0.10 mL

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Answers (1)
  1. 15 November, 22:57
    0
    V₁ = 10 mL

    Explanation:

    Given dа ta:

    Initial volume of HCl = ?

    Initial molarity = 3.0 M

    Final molarity = 0.10 M

    Final volume = 300.0 mL

    Solution:

    Formula:

    M₁V₁ = M₂V₂

    M₁ = Initial molarity

    V₁ = Initial volume of HCl

    M₂ = Final molarity

    V₂ = Final volume

    Now we will put the values.

    3.0 M * V₁ = 0.10 M*300.0 mL

    3.0 M * V₁ = 30 M. mL

    V₁ = 30 M. mL / 3.0 M

    V₁ = 10 mL
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