Calculate what volume of the following solutions is required to obtain 0.261 mol of each solute

(a) 0.281 M AICI:

(b) 2.19 M HCI

a) V sln = 0.9288 L

b) V sln = 0.1192 L

Explanation:

molarity (M) [=] mol solute / L solution

∴ mol solute = 0.261 mol

a) C AlCl = 0.281 M

⇒ V sln = (0.261 mol) * (L sln/0.281 mol)

⇒ V sln = 0.9288 L

b) C HCl = 2.19 M

⇒ V sln = (0.261 mol) * (L/2.19 mol)

⇒ V sln = 0.1192 L