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29 December, 15:26

How many milliliters of 1.0m agno3 are needes to provide 169.9 g of agno3?

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Answers (2)
  1. 29 December, 15:33
    0
    The molar mass of silver nitrate is 169.87 g/mol

    Therefore the number of moles in 169.9 g will be;

    = 169.9/169.87

    = 1 mole

    Therefore; since the molarity is 1.0 M

    then the volume = 1/1 = 1 liter which is equivalent to 1000ml

    Thus, the answer is 1000 ml
  2. 29 December, 15:40
    0
    The number of Ml of 1.0 AgNo3 needed to provide 169.9 0f AgNO3 is calculated as follows

    find the moles of AgNo3

    = mass/molar mass = 169.9/169.87 = 1 mole

    volume in Ml = moles / molarity x1000

    = 1/1 x1000 = 1000 ml
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