This is the equation for the dissociation of ammonia gas at 293 K. H = 145 kJ and S = 195 J/k.

2NH3 (g) N2 (g) + 3H2 (g)

Which correctly states the G for this dissociation and whether the process is spontaneous or nonspontaneous? Use G = H - TS.

Question

Evelin

Chemistry

23 October, 08:35

This is the equation for the dissociation of ammonia gas at 293 K. H = 145 kJ and S = 195 J/k.

2NH3 (g) N2 (g) + 3H2 (g)

Which correctly states the G for this dissociation and whether the process is spontaneous or nonspontaneous? Use G = H - TS.

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Lillian Salazar · Answer 1

We are given the equation for the dissociation of ammonia gas at 293 K.

2NH3 (g) = = > N2 (g) + 3H2 (g)

and H = 145 kJ; S = 195 J/K

To determine the Gibb's Free Energy for this reaction, use the formula:

G = H - TS

substitute the given values:

G = 145x10^3 J - 293K * 195 J/K

G = 87865 Joules

The dissociation of ammonia gas has a positive Gibb's Free Energy, thus, the reaction is not spontaneous. Spontaneous reactions have Gibb's Free Energy which is less than zero or a negative number.

This is the equation for the dissociation of ammonia gas at 293 K. H = 145 kJ and S = 195 J/k.2NH3 (g) N2 (g) + 3H2 (g)Which correctly states the G for this dissociation and whether the process is spontaneous or nonspontaneous? Use G = H - TS.

This is the equation for the dissociation of ammonia gas at 293 K. H = 145 kJ and S = 195 J/k.

2NH3 (g) N2 (g) + 3H2 (g)

Which correctly states the G for this dissociation and whether the process is spontaneous or nonspontaneous? Use G = H - TS.