Ask Question
25 August, 16:59

In a second trial of this experiment, the molarity of koh (aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what is the percent error in the second trial?

+4
Answers (1)
  1. 25 August, 17:02
    0
    The % error in the second trial is calculated as follows

    % error = actual molarity / theoretical molarity x100

    = 0.83/0.95 x100 = 87.4% error of second trial
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “In a second trial of this experiment, the molarity of koh (aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what is the ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers