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24 September, 20:02

A sample of solid NH 4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (atm) of ammonia, assuming that some solid NH 4HS remains.

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  1. 24 September, 20:24
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    The answer to the question is

    The equilibrium partial pressure (atm) of ammonia, assuming that some solid NH₄HS remains 0.26 atm.

    Explanation:

    To solve the question, we write out the chemical equation as follows

    NH₄HS (s) ⇄ NH₃ (g) + H₂S (g)

    From the above equation, it is observed that only the gaseous products contribute to the partial pressure

    Kp = PNH₃·PH₂S where at Kp = 0.070 and PNH₃, PH₂S are the partial pressures of the gases

    However since the number of moles of both gases are equal, therefore by Avogadro's law PNH₃ = PH₂S

    Then PNH₃ = √ (0.07) = PH₂S = 0.2645 atm. ≅ 0.26 atm.
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