A container holds 7.2 L of nitrogen at 25 °C. What will be its volume if the temperature increases

to 70 °C?

Hint: Use Charles' Law - (V/T1) = (V2/T2)

Answer: 8.23L

Explanation:

Initial volume of nitrogen V1 = 7.2 L

Initial temperature T1 = 25 °C

Convert temperature in Celsius to Kelvin

(25 °C + 273 = 298K)

New volume V2 = ?

New Temperature T2 = 70 °C

(70°C + 273 = 343K)

Since, volume and temperature are involved while pressure is constant, apply the formula for Charles' Law:

(V1/T1) = (V2/T2)

7.2L/298K = V2/343K

0.024 = V2/343K

To get V2, cross multiply

V2 = 0.024 x 343

V2 = 8.23L

Thus, the new volume of nitrogen is 8.23 liters