Ask Question
9 November, 17:06

How many moles of solute particles are present in 100.0 ml of 2.50 m (nh4) 3po4?

+4
Answers (1)
  1. 9 November, 17:30
    0
    The moles of solute particles that are present in 100.0 ml of 2.50M (NH4) 3Po4 is 0.25 moles

    calculation

    moles=volume in liters x molarity

    volume in liters=100/1000 = 0.1L

    molarity=2.50M

    moles is therefore = 2.50 x0.1=0.25moles
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many moles of solute particles are present in 100.0 ml of 2.50 m (nh4) 3po4? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers