Arrange the following in correct sequence: 1 Ammonia is converted to urea in the liver. 2 Oxidative deamination of an amino acid. 3 Urea is eliminated by the kidney. 4 Ammonia and keto acids are formed.

Question

Adriana Mckee

Chemistry

1 April, 08:03

Arrange the following in correct sequence: 1 Ammonia is converted to urea in the liver. 2 Oxidative deamination of an amino acid. 3 Urea is eliminated by the kidney. 4 Ammonia and keto acids are formed.

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Answers (1)

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Faith Ferguson · Answer 1

Answer:The correct sequence is as follows:

Oxidative deamination of an amino acid. Ammonia and keto acids are formed. Ammonia is converted to urea in the liver. Urea is eliminated by the kidney.

Explanation:

The food that we consume contain several macromolecules, which is broken down in its simpler form in the process of digestion. Some are stored while excess is eliminated from our body. Protein is broken down into amino acids and the excess amino acids travels from the intestine to the liver where its elimination process begins.

in the process of transamination, it is converted into glutamic acid and alpha ketoacid. in the next step, oxidative deamination takes place where glutamic acid is converted back to alpha ketoglutaric acid and ammonia. Ammonia if accumulated in the body causes toxicity so its immediately converted into urea by the liver cells in the process called ornithine cycle. The urea, thus, is released into the boodstream where it is transported to the kidney, which in turn excrete it out in the urine.