Calculate the percent by mass of a solution containing 0.21 moles of C12H22O11 (gram-molecular mass = 342 g/mole) in 250 g of water.

28.728%

Explanation:

We are given;

Moles of the solute, C12H22O11 = 0.21 moles

Molar mass of C₁₂H₂₂O₁₁ = 342 g/mol

Mass of the solvent water = 250 g

We need to calculate the percent by mass of a solution

Step 1: Calculate the mass of the solute

Mass = Number of moles * Molar mass

Therefore;

Mass of solute = 0.21 moles * 342 g/mol

= 71.82 g

Step 2: Calculate the percent by mass of the solution

% by mass = (Mass of solute : mass of the solution) * 100

= (71.82 g : 250 g) * 100

= 28.728%

Therefore, the percent by mass of the solution is 28.728%