Ask Question
19 December, 11:57

A 76.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 153 mL of water. What is the final concentration?

+5
Answers (1)
  1. 19 December, 12:18
    0
    The answer to your question is: Molarity = 0.30

    Explanation:

    Data

    V1 = 76 ml

    C1 = 1.4 M

    V2 = 208 ml

    V3 = 104 ml

    V water = 153 ml

    Process

    C1V1 = C2V2

    C2 = C1V1 / V2

    C2 = (1.4) (76) / 208

    C2 = 0.51 M

    Molarity = moles / volume

    moles = Molarity x volume

    moles = 0.51 x 0.208

    moles = 0.11 Final volume = 0.208 + 0.153

    Molarity = 0.11 / 0.361

    Molarity = 0.30
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 76.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 153 ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers