A 76.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 153 mL of water. What is the final concentration?

The answer to your question is: Molarity = 0.30

Explanation:

Data

V1 = 76 ml

C1 = 1.4 M

V2 = 208 ml

V3 = 104 ml

V water = 153 ml

Process

C1V1 = C2V2

C2 = C1V1 / V2

C2 = (1.4) (76) / 208

C2 = 0.51 M

Molarity = moles / volume

moles = Molarity x volume

moles = 0.51 x 0.208

moles = 0.11 Final volume = 0.208 + 0.153

Molarity = 0.11 / 0.361

Molarity = 0.30