What is the number of moles of gas contained in a 3 L vessel at 300 K with a pressure of 1.50 atm? (Given: R = 0.08205 L∙atm/mol∙K) 4.5 mol 0.18 mol 24.63 mol 5.47 mol 1.8 mol

Question

Delaney Schmidt

Chemistry

10 July, 08:26

What is the number of moles of gas contained in a 3 L vessel at 300 K with a pressure of 1.50 atm? (Given: R = 0.08205 L∙atm/mol∙K) 4.5 mol 0.18 mol 24.63 mol 5.47 mol 1.8 mol

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Alexzander Frederick · Answer 1

P = 1.50 atm

V = 3 L

R = 0.08205 L∙atm/mol∙K

T = 300 K

n = ?

we all this information, we can tell that we need to use ideal gas formula

PV = nRT

if we rearrange the formula for n, we get--> n = PV / RT

let's plug in the values.

n = 1.5 x 3 / (0.08205 x 300) = 0.18 moles