For the reaction, calculate how many grams of the product form when 23.4 g of ca completely reacts. assume that there is more than enough of the other reactant.

Question

Myla Flynn

Chemistry

1 December, 01:07

For the reaction, calculate how many grams of the product form when 23.4 g of ca completely reacts. assume that there is more than enough of the other reactant.

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Jordon Mitchell · Answer 1

Answer is: mass of product is 649.35 g.

Balanced chemical reaction: Ca (s) + Cl₂ (g) → CaCl ₂ (s).

m (Ca) = 23.4 g.

n (Ca) = m (Ca) : M (Ca).

n (Ca) = 23.4 g : 40 g/mol.

n (Ca) = 0.585 mol.

From chemical reaction: n (Ca) : n (CaCl₂) = 1 : 1.

n (CaCl₂) = 0.585 mol.

m (CaCl₂) = 0.585 mol · 111 g/mol.

m (CaCl₂) = 649.35 g.